Monday, March 6th

by nickhershman Add Your Comment
In class today students had about 1/2 hour to work silently on the chapter review assignment and then time to compare. I answered questions on a few area problems. One nice question was whether a square peg in a circular hole is a tighter fit than a circular peg in a square hole? The ratio of the area of a square peg to the smallest round hole it can fit through is 2 : pi which we can reason must be less than 66 dfrac{2}{3}% while the ratio of the area of the round peg to the smallest square hole's area is pi : 4 which we can reason is greater than 75%. So, the round peg in a square hole is a tighter fit.

Study Guide

  • Be able to explain the area formula for any 3- or 4-sided polygon and also any regular n-gon.
  • Explain why the area of a circle is pi r^2 and the circumference is pi cdot D or 2 pi r
  • Explain why the lateral surface area of any pyramid with a regular polygon base is dfrac{P cdot l}{2}
  • Explain why the formula for the surface area of a cone is pi r^2 + pi r l or pi r(r + l)
  • Solve problems involving area of geometric shapes, express answers in exact form (in terms of pi, in simplest radical form, using fractions)
  • Understand problems similar to homework problems throughout the unit.

Assignment: Chapter 8 Review on p. 455: 1-47 (odds) + 38. Priority problems (to be done first) were 25, 38, 39, 45.