Tuesday, Mar 21

In class today the lesson focused on the relationship between the Pythagorean Theorem and the equation for a circle. Students relate the distance between (a, b) and (x, y) to the pythagorean theorem, and realize that d = sqrt{(x - a)^2 + (y-b)^2} and then we note that the equation of a circle whose center is at (a, b) and which has a radius of r is

r^2 = (x - a)^2 + (y-b)^2


r =pm sqrt{(x-a)^2 + (y-b)^2}

Note, I just now realized that I did not include pm in the notes from class.

Handed back today: Chapter 8 Assessments on Criteria A and C. Students received two scores on the latest assessment.

Today's assignment: 9.5 on p. 489: 1-12

Upcoming: Assessment on Chapter 9 at end of week. See me if you plan to be absent on Thursday/Friday.